If exactly one root of the quadratic equation lies in the interval

MATHEMATICS · Single correct · A Level · Mathematics · Algebra and Functions · Algebra and Functions

Problem

If exactly one root of the quadratic equation x2−(a+1)x+2a=0x^2 - (a+1)x + 2a = 0 lies in the interval (0,3)(0, 3), then the set of value ' aa ' is given by: (a) (−∞,0)∪(6,∞)(-\infty, 0) \cup (6, \infty) (b) (−∞,0]∪(6,∞)(-\infty, 0] \cup (6, \infty) (c) (−∞,0]∪[6,∞)(-\infty, 0] \cup [6, \infty) (d) (0,6)(0, 6)

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