A network contains two ideal sources and four resistors connected as follows

PHYSICS · Subjective · CBSE · Physics · Current Electricity · Current Electricity

Problem

A network contains two ideal sources and four resistors connected as follows. • Battery

E_1 = 24\,\text{V}

is connected between nodes

P

(positive) and

Q

(negative). • Battery

E_2 = 12\,\text{V}

is connected between nodes

R

(positive) and

S

(negative), with node

S

coinciding with node

P

so that the two sources oppose each other in one loop. • Resistor

R_1 = 8\,\Omega

joins nodes

P

and

R

. • Resistor

R_2 = 5\,\Omega

joins nodes

R

and

Q

. • Resistor

R_3 = 10\,\Omega

joins nodes

Q

and

S

(that is, nodes

Q

and

P

). • Resistor

R_4 = 6\,\Omega

joins nodes

P

and

Q

directly. Assume clockwise branch currents

I_1

R_1

I_2

R_2

, and

I_3

R_4

. (a) Write the two independent closed-path equations and the single junction equation required to solve for

I_1

I_2

, and

I_3

. (b) Solve these equations to obtain numerical values of the three currents. (c) For each source and each resistor, compute the power supplied or absorbed. Verify that the total power supplied equals the total power dissipated in the network.

Related theory

Browse the problem library