A timing circuit in a stroboscopic lamp operates in two stages with a single capacitor

PHYSICS · Multi-part · A Level · Physics · Fields and their consequences · Fields and their consequences

Problem

A timing circuit in a stroboscopic lamp operates in two stages with a single 10 μF10\,\mu\text{F} capacitor. • Stage 1 (Charge): The capacitor is connected to a 12 V12\,\text{V} supply through resistor R1R_1 for exactly 20 ms20\,\text{ms}. • Stage 2 (Discharge): An electronic switch then instantly disconnects the supply and connects the capacitor across a different resistor R2R_2. After an additional 10 ms10\,\text{ms}, the voltage across the capacitor must have decayed to 37 percent of the value it had immediately after the charging stage ended. Both R1R_1 and R2R_2 must be chosen from the E24 series (… 820 Ω, 910 Ω, 1.0 kΩ, 1.1 kΩ, 1.2 kΩ, 1.3 kΩ, …). (a) Determine the minimum time constant required during Stage 1 so that the capacitor reaches at least 86 percent of the 12 V12\,\text{V} supply voltage within 20 ms20\,\text{ms}. (b) Calculate the corresponding value of R1R_1 and identify the nearest E24 resistor that can be used. (c) Determine the time constant required during Stage 2 for the capacitor voltage to fall to 37 percent of its initial Stage 2 value within 10 ms10\,\text{ms}. (d) Calculate the value of R2R_2 that meets the discharge requirement and select the nearest E24 resistor. (e) Using the resistor values selected in parts (b) and (d), estimate the electrical energy dissipated in R2R_2 during the entire 10 ms10\,\text{ms} discharge interval. Express your answer in millijoules and outline all steps in your calculation.

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