For the circle

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

For the circle (x−4)2+(y+3)2=25(x - 4)^2 + (y + 3)^2 = 25, a point P(x1,y1)P(x_1, y_1) is chosen. Which condition must PP satisfy so that the tangent at PP to the circle can be written? (a) (x1+4)2+(y1−3)2=25(x_1 + 4)^2 + (y_1 - 3)^2 = 25 (b) x12+y12=25x_1^2 + y_1^2 = 25 (c) (x1−4)2+(y1+3)2=25(x_1 - 4)^2 + (y_1 + 3)^2 = 25 (d) (x1−4)2+(y1+3)2>25(x_1 - 4)^2 + (y_1 + 3)^2 > 25

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