An electric lift of mass is designed to move vertically upward with the help of a…

PHYSICS · Multi-part · CBSE · Physics · Work, Energy and Power · Work, Energy and Power

Problem

An electric lift of mass 800 kg800\,\text{kg} is designed to move vertically upward with the help of a motor rated at 12 kW12\,\text{kW}. When the lift moves, a constant frictional force of 1000 N1000\,\text{N} opposes its motion. (a) Calculate the total upward force that the motor must supply for the lift to move upward at constant speed. Take g=9.8 m s−2g = 9.8\,\text{m s}^{-2}. (b) Using the motor’s rated power, determine the maximum constant speed at which the lift can rise. Express the answer in m s−1\text{m s}^{-1}. (c) Convert this speed into km h−1\text{km h}^{-1} and comment briefly on whether it would be suitable for a passenger lift in a two-storey building.

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