The e.m.f. of the following Daniel cell at 298 K is When the concentration of is 1.0…

CHEMISTRY · Single correct · A Level · Chemistry · Electrode potentials · Electrode potentials

Problem

The e.m.f. of the following Daniel cell at 298 K is

E_1

\text{Zn} | \text{ZnSO}_4(0.01\text{M}) || \text{CuSO}_4(1.0\text{M}) | \text{Cu}

When the concentration of

\text{ZnSO}_4

is 1.0 M and that of

\text{CuSO}_4

is 0.01 M, the e.m.f. changed to

E_2

. What is the relationship between

E_1

and

E_2

? (a)

E_1 > E_2

(b)

E_1 < E_2

(c)

E_1 = E_2

(d)

E_2 = 0 \ne E_1