The three sides of a triangle are given by

MATHEMATICS · Single correct · CBSE · Mathematics · Straight Lines · Straight Lines

Problem

The three sides of a triangle are given by (x2−y2)(2x+3y−6)=0(x^2-y^2)(2x+3y-6)=0. If the point (−2,a)(-2,a) lies inside and (b,1)(b,1) lies outside the triangle, then (1) a∈(2,103); b∈(−1,1)a\in\left(2,\frac{10}{3}\right);\ b\in(-1,1) (2) a∈(−2,103); b∈(−1,92)a\in\left(-2,\frac{10}{3}\right);\ b\in\left(-1,\frac{9}{2}\right) (3) a∈(1,103); b∈(−3,5)a\in\left(1,\frac{10}{3}\right);\ b\in(-3,5) (4) None of these

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