Which of the following most likely explains why a graphing-calculator plot of on the…

MATHEMATICS · Single correct · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Which of the following most likely explains why a graphing-calculator plot of y=sin⁡ ⁣(1x)y=\sin\!\left(\dfrac{1}{x}\right) on the window −10≤x≤10-10\le x\le 10 and −1≤y≤1-1\le y\le 1 appears to settle into a single horizontal line near x=0x=0? (a) Because sin⁡ ⁣(1x)\sin\!\left(\dfrac{1}{x}\right) approaches 00 as x→0x\to 0, the graph levels off along the xx–axis. (b) The symmetric window causes the calculator to plot the positive and negative parts on top of each other, giving the illusion of a single horizontal line. (c) The calculator evaluates only finitely many evenly–spaced xx–values; near x=0x=0 the oscillations are too rapid, so successive sampled points all lie very close to y=0y=0, and the display connects them as a straight horizontal segment. (d) The yy–range −1≤y≤1-1\le y\le 1 is so small compared with the screen’s pixel height that all the peaks and troughs fall in the same pixel row, hiding the oscillations.

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