If the given lines and are perpendicular

MATHEMATICS · Subjective · CBSE · Mathematics · Three-Dimensional Geometry · Three-Dimensional Geometry

Problem

If the given lines x−1−3=y−22k=z−32\frac{x-1}{-3} = \frac{y-2}{2k} = \frac{z-3}{2} and x−13k=y−11=z−6−5\frac{x-1}{3k} = \frac{y-1}{1} = \frac{z-6}{-5} are perpendicular, then kk is (A) −10-10 (B) 107\frac{10}{7} (C) −107-\frac{10}{7} (D) −710-\frac{7}{10}

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