The electric potential as a function of distance (in metre) is given by V = (5x^2 +…

PHYSICS · Single correct · CBSE · Physics · Electrostatic Potential and Capacitance · Electrostatic Potential and Capacitance

Problem

The electric potential VV as a function of distance xx (in metre) is given by V=(5x2+10x−9) volt.V = (5x^2 + 10x - 9) \text{ volt.} The value of electric field at x=1x = 1 m would be: (a) -20 volt/m (b) 6 volt/m (c) 11 volt/m (d) -23 volt/m

Related theory

Browse the problem library