Methanol is synthesized according to when at a given temperature

CHEMISTRY · Single correct · A Level · Chemistry · Chemical equilibria (Le Chatelier’s principle and Kc) · Chemical equilibria (Le Chatelier’s principle and Kc)

Problem

Methanol is synthesized according to CO(g)+2H2(g)⇌CH3OH(g)\text{CO}(g) + 2\text{H}_2(g) \rightleftharpoons \text{CH}_3\text{OH}(g) when Kc=0.50K_c = 0.50 at a given temperature. An equilibrium mixture in a 2.0 L2.0\,\text{L} vessel contains 1.0 mol1.0\,\text{mol} of CO, 2.0 mol2.0\,\text{mol} of H2_2, and 0.50 mol0.50\,\text{mol} of CH3_3OH. If 0.30 mol0.30\,\text{mol} of CH3_3OH is rapidly removed while the volume remains constant, what will be the net direction of the reaction as the system moves toward a new equilibrium? (a) Toward reactants, because decreasing [CH3OH][\text{CH}_{3}\text{OH}] lowers the total pressure, so the equilibrium shifts toward the side with more gas molecules. (b) Toward products, because the new value of QcQ_{c} is less than KcK_{c}. (c) Toward reactants, because the new value of QcQ_{c} is less than KcK_{c}. (d) No net change; QcQ_{c} remains equal to KcK_{c} unless the temperature changes.

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