For a series LCR circuit the inductance is and the resistance is

PHYSICS · Single correct · CBSE · Physics · Alternating Current · Alternating Current

Problem

For a series LCR circuit the inductance is L=0.5 HL = 0.5\,\text{H} and the resistance is R=5 ΩR = 5\,\Omega. The resonant angular frequency is ω0=200 rad s−1\omega_0 = 200\,\text{rad s}^{-1}. Using the small-RR approximation, the higher half-power angular frequency ω2\omega_2 is nearly (a) 210 rad s−1210\,\text{rad s}^{-1} (b) 195 rad s−1195\,\text{rad s}^{-1} (c) 205 rad s−1205\,\text{rad s}^{-1} (d) 202.5 rad s−1202.5\,\text{rad s}^{-1}

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