For a photon

PHYSICS · Single correct · CBSE · Physics · Dual Nature of Radiation and Matter · Dual Nature of Radiation and Matter

Problem

For a photon, the relations E=hfE=hf and p=E/cp=E/c hold. Eliminating EE leads to a direct relation between momentum pp and wavelength λ\lambda. Which of the following correctly gives this relation? (a) p=h2πλp = \dfrac{h}{2\pi \lambda} (b) p=2hλp = \dfrac{2 h}{\lambda} (c) p=hλp = \dfrac{h}{\lambda} (d) p=2πhλp = \dfrac{2\pi h}{\lambda}

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