During one route for synthesizing liquid methanol

CHEMISTRY · Subjective · A Level · Chemistry · Energetics · Energetics

Problem

During one route for synthesizing liquid methanol, the following steps are carried out: (1) CO2(g)+H2(g)→CO(g)+H2O(g)CO_2(g) + H_2(g) \to CO(g) + H_2O(g)  ΔH1=+41.2 kJ\Delta H_1 = +41.2\,\text{kJ} (2) CO(g)+2 H2(g)→CH3OH(g)CO(g) + 2\,H_2(g) \to CH_3OH(g)  ΔH2=−90.7 kJ\Delta H_2 = -90.7\,\text{kJ} (3) H2O(g)→H2O(l)H_2O(g) \to H_2O(l)  ΔH3=−44.0 kJ\Delta H_3 = -44.0\,\text{kJ} (4) CH3OH(g)→CH3OH(l)CH_3OH(g) \to CH_3OH(l)  ΔH4=−38.0 kJ\Delta H_4 = -38.0\,\text{kJ} Calculate the overall enthalpy change, in kJ mol−1\text{kJ mol}^{-1} of CH3OH(l)CH_3OH(l) formed, for the net reaction CO2(g)+3 H2(g)→CH3OH(l)+H2O(l)CO_2(g) + 3\,H_2(g) \to CH_3OH(l) + H_2O(l).

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