The differential equation has equilibrium solutions at ,

MATHEMATICS · Single correct · AP · Calculus AB · Differential Equations · Differential Equations

Problem

The differential equation dydt=y3−4y\dfrac{dy}{dt}=y^{3}-4y has equilibrium solutions at y=−2y=-2, y=0y=0, and y=2y=2. Which statement most accurately describes the stability of these equilibria and the long-term behavior of a solution satisfying y(0)=1y(0)=1? (a) y=−2y=-2 and y=0y=0 are unstable, y=2y=2 is stable, and the solution with y(0)=1y(0)=1 approaches y=2y=2 as t→∞t\to\infty. (b) y=−2y=-2 and y=2y=2 are unstable, y=0y=0 is stable, and the solution with y(0)=1y(0)=1 approaches y=0y=0 as t→∞t\to\infty. (c) y=−2y=-2 and y=2y=2 are stable, y=0y=0 is unstable, and the solution with y(0)=1y(0)=1 approaches y=2y=2 as t→∞t\to\infty. (d) y=−2y=-2 is stable, y=0y=0 and y=2y=2 are unstable, and the solution with y(0)=1y(0)=1 approaches y=−2y=-2 as t→∞t\to\infty.

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