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MATHEMATICS · Subjective · CBSE · Mathematics · Three-Dimensional Geometry · Three-Dimensional Geometry
Problem 5. Find the vector equation of the line passing through the point ( 1 , 2 , − 4 ) (1,2,-4) ( 1 , 2 , − 4 ) x − 8 3 = y + 19 − 16 = z − 10 7 and x − 15 3 = y − 29 8 = z − 5 − 5 . \frac{x-8}{3}=\frac{y+19}{-16}=\frac{z-10}{7} \text { and } \frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5} . 3 x − 8 = − 16 y + 19 = 7 z − 10 and 3 x − 15 = 8 y − 29 = − 5 z − 5 . Browse the problem library