A mixer holds a solution whose concentration is

MATHEMATICS · Single correct · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

A mixer holds a solution whose concentration is C(t)=m(t)V(t)C(t)=\dfrac{m(t)}{V(t)}. At a particular moment, m=500 gm=500\text{ g} and V=250 LV=250\text{ L}. The salt is being added at dmdt=2 g min−1\dfrac{dm}{dt}=2\text{ g min}^{-1} while the solution drains at dVdt=−4 L min−1\dfrac{dV}{dt}=-4\text{ L min}^{-1}. Determine dCdt\dfrac{dC}{dt} at that moment (in g L−1 min−1\text{g L}^{-1}\text{ min}^{-1}). (a) 0.0320.032 (b) 0.040.04 (c) −0.04-0.04 (d) −0.024-0.024

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