For a particle

MATHEMATICS · Single correct · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

For a particle, displacement as a function of time is x(t)=t3−6t2+9t+2x(t)=t^{3}-6t^{2}+9t+2 (in metres). At what time does its velocity first become zero and what is the magnitude of acceleration at that instant? (a) t=1 s,  ∣a∣=6 m s−2t=1\,\text{s},\;|a|=6\,\text{m\,s}^{-2} (b) t=3 s,  ∣a∣=6 m s−2t=3\,\text{s},\;|a|=6\,\text{m\,s}^{-2} (c) t=1 s,  ∣a∣=0 m s−2t=1\,\text{s},\;|a|=0\,\text{m\,s}^{-2} (d) t=4 s,  ∣a∣=12 m s−2t=4\,\text{s},\;|a|=12\,\text{m\,s}^{-2}

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