A spaceship orbits around a planet at a height of from its surface

PHYSICS · Single correct · CBSE · Physics · Gravitation · Gravitation

Problem

A spaceship orbits around a planet at a height of 20 km20\,\text{km} from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours24\,\text{hours} around the planet? Given: Mass of planet =8×1022 kg= 8 \times 10^{22}\,\text{kg}; Radius of planet =2×106 m= 2 \times 10^6\,\text{m}, Gravitational constant G=6.67×10−11 N m2/kg2G = 6.67 \times 10^{-11}\,\text{N m}^2/\text{kg}^2. (1) 9 (2) 11 (3) 13 (4) 17

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