A straight line through the vertex of a intersects the side at and the circumcircle of at

MATHEMATICS · Single correct · ICSE · Mathematics · Geometry · Geometry

Problem

A straight line through the vertex PP of a △PQR\triangle PQR intersects the side QRQR at SS and the circumcircle of △PQR\triangle PQR at TT. If SS is not the centre of the circumcircle, then (1) 1PS+1ST<2QS×SR\frac{1}{PS}+\frac{1}{ST}<\frac{2}{\sqrt{QS\times SR}} (2) 1PS+1ST>2QS×SR\frac{1}{PS}+\frac{1}{ST}>\frac{2}{\sqrt{QS\times SR}} (3) 1PS+1ST<4QR\frac{1}{PS}+\frac{1}{ST}<\frac{4}{QR} (4) 1PS+1ST>4QR\frac{1}{PS}+\frac{1}{ST}>\frac{4}{QR}

Related theory

Browse the problem library