Let be the temperature (in °C) of a solution

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

Let TT be the temperature (in °C) of a solution, which is a differentiable function of its volume VV (in liters). The volume VV is, in turn, a differentiable function of time tt (in seconds). Which of the following correctly expresses dTdt\dfrac{dT}{dt} in terms of dTdV\dfrac{dT}{dV} and dVdt\dfrac{dV}{dt}? (a) −dTdV dVdt-\dfrac{dT}{dV}\,\dfrac{dV}{dt} (b) dTdV dVdt\displaystyle \frac{dT}{dV}\,\frac{dV}{dt} (c) 12 dTdV dVdt\displaystyle \frac12\,\frac{dT}{dV}\,\frac{dV}{dt} (d) 2 dTdV dVdt\displaystyle 2\,\frac{dT}{dV}\,\frac{dV}{dt}

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