The values of two phenolic acids at are given below
CHEMISTRY · Multi-part · AP · Chemistry · Acids and Bases · Acids and Bases
Problem
The pKa values of two phenolic acids at 298K are given below.
• Phenol: pKa=10.00
• p-Nitrophenol: pKa=7.15
For any acid, the standard free energy of deprotonation is related to its pKa by
ΔG∘=2.303RTpKa,
where R=8.314J⋅mol−1⋅K−1 and T=298K.
(1) Part 1: (a) Calculate ΔG∘ (in kJ⋅mol−1) for the deprotonation of phenol.
(2) Part 2: (b) Calculate ΔG∘ (in kJ⋅mol−1) for the deprotonation of p-nitrophenol.
(3) Part 3: (c) Determine ΔΔG∘, the difference in standard free energy of deprotonation between the two acids, and state which conjugate base is thermodynamically more stable.