A perpendicular force of produces a torque of about a fixed point

PHYSICS · Single correct · CBSE · Physics · System of Particles and Rotational Motion · System of Particles and Rotational Motion

Problem

A perpendicular force of 3.0×102 N3.0 \times 10^{2}\,\text{N} produces a torque of 1.2×103 N m1.2 \times 10^{3}\,\text{N m} about a fixed point. The perpendicular distance between the point and the line of action of the force is (a) 0.40 m0.40\,\text{m} (b) 40 m40\,\text{m} (c) 4.0 m4.0\,\text{m} (d) 0.25 m0.25\,\text{m}

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