A beverage manufacturer is designing a closed right circular aluminum can to hold of soda

MATHEMATICS · Multi-part · A Level · Mathematics · Differentiation · Differentiation

Problem

A beverage manufacturer is designing a closed right circular aluminum can to hold 1 L1\,\text{L} of soda, assuming 1000 cm31000\,\text{cm}^3 of liquid. The aluminum used for the sidewall costs 0.0100.010 dollars per cm2\text{cm}^2, while the reinforced aluminum used for each lid (top and bottom) costs 0.0250.025 dollars per cm2\text{cm}^2. Ignore any loss of material at seams. (a) Let rr be the interior radius (in cm) and hh the interior height (in cm). Derive an expression C(r,h)C(r,h) for the total manufacturing cost, in dollars, of one can. (b) Write the volume constraint in terms of rr and hh, then solve this equation for hh in terms of rr. (c) Substitute the expression for hh from part (b) into C(r,h)C(r,h) to obtain CC as a function of rr only. Determine the critical value of rr that minimizes C(r)C(r). Show all calculus work, including derivative computations. (d) Verify that the critical value found in part (c) yields a minimum total cost, and compute the corresponding height hh. (e) Interpret your result in context by stating the optimal radius, height, and minimum material cost per can to the nearest 0.00010.0001 dollar.

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