For , define . Prove that by completing the steps…

MATHEMATICS · Multi-part · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

For x≠−2x\neq -2, define f(x)=2x+1x+2f(x)=\dfrac{2x+1}{x+2}. Prove that lim⁡x→1f(x)=1\displaystyle \lim_{x\to 1} f(x)=1 by completing the steps below. (a) Derive an expression for ∣f(x)−1∣|f(x)-1| that isolates a factor of ∣x−1∣|x-1| in the numerator. (b) Explain why the denominator of f(x)f(x) is bounded away from zero when ∣x−1∣<1|x-1|<1. Provide a numerical lower bound for ∣x+2∣|x+2| under this assumption. (c) Combine your results from parts (a) and (b) to obtain an inequality of the form ∣f(x)−1∣⩽C∣x−1∣|f(x)-1| \leqslant C|x-1|, where CC is a positive constant you must determine. (d) For an arbitrary ε>0\varepsilon>0, choose an appropriate δ\delta that ensures ∣f(x)−1∣<ε|f(x)-1|<\varepsilon whenever ∣x−1∣<δ|x-1|<\delta and ∣x−1∣<1|x-1|<1. Conclude the proof with a clear logical statement connecting ε\varepsilon, δ\delta, and the limit.

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