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Three vectors ( )
MATHEMATICS · Single correct · CBSE · Mathematics · Vector Algebra · Vector Algebra
Problem Three vectors a \mathbf{a} a ( ∣ a ∣ ≠ 0 |\mathbf{a}| \neq 0 ∣ a ∣ = 0 ), b \mathbf{b} b and c \mathbf{c} c are such that a × b = 3 a × c \mathbf{a} \times \mathbf{b} = 3\mathbf{a} \times \mathbf{c} a × b = 3 a × c . Also, ∣ a ∣ = ∣ b ∣ = 1 |\mathbf{a}| = |\mathbf{b}| = 1 ∣ a ∣ = ∣ b ∣ = 1 and ∣ c ∣ = 1 3 |\mathbf{c}| = \frac{1}{3} ∣ c ∣ = 3 1 . If the angle between b \mathbf{b} b and c \mathbf{c} c is 60 ∘ 60^\circ 6 0 ∘ , then
(1) b = 3 c + a \mathbf{b} = 3\mathbf{c} + \mathbf{a} b = 3 c + a
(2) b = 3 c − a \mathbf{b} = 3\mathbf{c} - \mathbf{a} b = 3 c − a
(3) a = 6 c + 2 b \mathbf{a} = 6\mathbf{c} + 2\mathbf{b} a = 6 c + 2 b
(4) a = 6 c − 2 b \mathbf{a} = 6\mathbf{c} - 2\mathbf{b} a = 6 c − 2 b
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