Let be a real-valued function with and

MATHEMATICS · Single correct · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Let gg be a real-valued function with g(1)=−5g(1)=-5 and g(4)=3g(4)=3. The function is discontinuous at exactly one point in the interval (1,4)(1,4). Which statement best describes what can be concluded about the equation g(x)=0g(x)=0 on (1,4)(1,4)? (a) A solution is guaranteed because the values at x=1x=1 and x=4x=4 have opposite signs. (b) A solution is not guaranteed because the function is not continuous on the entire interval. (c) No solution exists because the function is discontinuous at a point inside the interval. (d) At least two solutions exist because the function changes sign and has a discontinuity.

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