Which statement correctly defines an equilibrium solution of the first-order…

MATHEMATICS · Single correct · AP · Calculus AB · Differential Equations · Differential Equations

Problem

Which statement correctly defines an equilibrium solution of the first-order differential equation dydt=f(t,y)\dfrac{dy}{dt}=f(t,y)? (a) An individual point (t0,y0)(t_0,y_0) where f(t0,y0)=0f(t_0,y_0)=0.},{ (b) A solution of the form y=cy=c for which f(t,c)=0f(t,c)=0 for every value of tt.},{ (c) A solution curve that passes through the origin and has zero slope there. (d) Any value of tt at which the function y(t)y(t) attains a local maximum or minimum.

Related theory

Browse the problem library