The voltage of the cell given below is : Pt _ H _2 ,| , NaHSO _3 (0.4 M ) ,| , Na _2…

CHEMISTRY · Subjective · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

The voltage of the cell given below is −0.46 V-0.46\text{ V}: PtH2 ∣ NaHSO3 (0.4 M) ∣ Na2SO3 (6.44×10−3 M) ∣ Zn2+ (0.3 M) ∣ Zn(s)\text{Pt}_{\text{H}_2}\,|\,\text{NaHSO}_3\ (0.4\text{ M})\,|\,\text{Na}_2\text{SO}_3\ (6.44\times 10^{-3}\text{ M})\,|\,\text{Zn}^{2+}\ (0.3\text{ M})\,|\,\text{Zn}(s) Also, Zn2++2e⟶Zn(s)\text{Zn}^{2+} + 2e \longrightarrow \text{Zn}(s), E∘=−0.763 VE^\circ = -0.763\text{ V}. Calculate the value of K2K_2, where K2=[H+][SO32−][HSO3−]K_2 = \frac{[\text{H}^+][\text{SO}_3^{2-}]}{[\text{HSO}_3^-]}.

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