CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

ddx[eaxcos⁡(bx+c)]=\displaystyle\frac{d}{dx}\left[e^{ax}\cos(bx+c)\right]= (a) eax[acos⁡(bx+c)−bsin⁡(bx+c)]e^{ax}\left[a\cos(bx+c)-b\sin(bx+c)\right] (b) eax[asin⁡(bx+c)−bcos⁡(bx+c)]e^{ax}\left[a\sin(bx+c)-b\cos(bx+c)\right] (c) eax[cos⁡(bx+c)−sin⁡(bx+c)]e^{ax}\left[\cos(bx+c)-\sin(bx+c)\right] (d) None of these

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