In ΔABC, points D and E are taken on AB and AC respectively such that AD:DB=1:2 and AE:EC=1:2. Join DE. Further, points F and G are taken on AD and AE respectively so that AF:FD=1:2 and AG:GE=1:2. Join FG.
(i) ΔADE is similar to ΔABC and hence obtain the ratio of their areas.
(ii) ΔAFG is similar to ΔADE.
(iii) Hence show that the area of ΔAFG is 811 of the area of ΔABC.