AoPS

MATHEMATICS · Single correct · AoPS · Mathematics · Sequences & Series · Sequences & Series

Problem

If ∑r=1nTr=n(n+1)(n+2)3\sum_{r=1}^{n} T_r = \frac{n(n+1)(n+2)}{3}, then lim⁡n→∞∑r=1n2008Tr=\lim_{n \to \infty} \sum_{r=1}^{n} \frac{2008}{T_r} = (a) 2008 (b) 3012 (c) 4016 (d) 8032

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