For the reaction

CHEMISTRY · Single correct · AP · Chemistry · Kinetics · Kinetics

Problem

For the reaction P+Q→S+TP + Q \rightarrow S + T, the following two-step mechanism has been proposed. Step 1 (slow): P+Q→R+SP + Q \rightarrow R + S Step 2 (fast): R→TR \rightarrow T A student claims that species RR is a catalyst for the reaction. Which statement best explains why this claim is incorrect? (a) RR is involved in the slow, rate \,–determining step, and catalysts can only participate in fast steps; therefore RR cannot be a catalyst. (b) RR is produced in Step \,1 rather than being initially present, and its net concentration does not remain constant during the reaction. (c) RR does not appear in the overall balanced equation, so it cannot be acting as a catalyst. (d) RR appears and is consumed, so it behaves as a reactant rather than as a catalyst, which must remain entirely unchanged during the mechanism.

Related theory

Browse the problem library