On the interval

MATHEMATICS · Single correct · CBSE · Mathematics · Applications of Derivatives · Applications of Derivatives

Problem

On the interval [−5,4][-5,4], the function h(x)=x3−12x+1h(x)=x^3-12x+1 has stationary points at x=−2x=-2 and x=2x=2. At which point in this interval does h(x)h(x) attain its absolute minimum value? (a) x=−2x=-2 (b) x=0x=0 (c) x=−5x=-5 (d) x=2x=2

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