Minimum value of is :

MATHEMATICS · Single correct · CBSE · Mathematics · Applications of Derivatives · Applications of Derivatives

Problem

Minimum value of y=x2−3x+5,x∈[−4,1]y = x^2 - 3x + 5, x \in [-4, 1] is : (a) 3 (b) 114\frac{11}{4} (c) 0 (d) 9

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