Given that the quadratic equation has no real roots

MATHEMATICS · Subjective · CBSE · Mathematics · Polynomials · Polynomials

Problem

Given that the quadratic equation ax2+bx+c=0ax^2+bx+c=0 has no real roots, but Mr X got two roots 2 and 4. Since he wrote down a wrong value of 'a', Mr X also got two roots -1 and 4 because he wrote the sign of a term wrongly. Then, the value of 2b+3ca\frac{2b+3c}{a} is equal to

Related theory

Browse the problem library