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For a planet orbiting a star of mass
PHYSICS · Single correct · CBSE · Physics · Gravitation · Gravitation
Problem
For a planet orbiting a star of mass
M
M
M
, at an orbital radius of
R
R
R
, and with an orbital period
T
T
T
, Kepler's third law states that (1)
T
3
R
2
=
G
M
4
π
2
\frac{T^3}{R^2} = \frac{GM}{4\pi^2}
R
2
T
3
=
4
π
2
GM
(2)
T
3
R
2
=
4
π
2
G
M
\frac{T^3}{R^2} = \frac{4\pi^2}{GM}
R
2
T
3
=
GM
4
π
2
(3)
T
2
R
3
=
G
M
4
π
2
\frac{T^2}{R^3} = \frac{GM}{4\pi^2}
R
3
T
2
=
4
π
2
GM
(4)
T
2
R
3
=
4
π
2
G
M
\frac{T^2}{R^3} = \frac{4\pi^2}{GM}
R
3
T
2
=
GM
4
π
2
Related theory
Planetary Motion & Orbits
Gravitation
Kepler's laws
Kepler's laws of planetary motion
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