A three-step gas-phase mechanism converts A(g) to D(g) through two observable…

CHEMISTRY · Multi-part · AP · Chemistry · Kinetics · Kinetics

Problem

A three-step gas-phase mechanism converts A(g) to D(g) through two observable intermediates, B(g) and C(g). A researcher constructs an energy diagram whose salient numerical features are listed below (all energies are relative to A(g), which is assigned 0 kJ mol⁻¹). Step 1: A(g) → B(g) Transition-state energy = 48 kJ mol⁻¹ Energy of B(g) = 14 kJ mol⁻¹ Step 2: B(g) → C(g) Transition-state energy = 66 kJ mol⁻¹ Energy of C(g) = –5 kJ mol⁻¹ Step 3: C(g) → D(g) Transition-state energy = 42 kJ mol⁻¹ Energy of D(g) = –32 kJ mol⁻¹ Use these data to answer the following. (a) Calculate ΔH\Delta H for each of the three individual steps. (b) Determine the overall enthalpy change, ΔHoverall\Delta H_{\text{overall}}, for conversion of A(g) to D(g). (c) Identify the rate-determining step and justify your answer quantitatively. (d) A catalyst lowers the highest transition-state energy by 12 kJ mol⁻¹ without affecting any other energy values. Predict which step’s rate will be most strongly affected and explain your reasoning.

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