Solve for and check for extraneous solutions: 3 x+4 - 1 x-4 = 12 x^2-16

MATHEMATICS · Subjective · GCSE · Mathematics · Algebra · Algebra

Problem

Solve for xx and check for extraneous solutions: 3x+4−1x−4=12x2−16\frac{3}{x+4} - \frac{1}{x-4} = \frac{12}{x^2-16}

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