An electron ( ) enters a magnetic field with speed at an angle of to the field

PHYSICS · Single correct · CBSE · Physics · Moving Charges and Magnetism · Moving Charges and Magnetism

Problem

An electron (m=9.1×10−31 kgm=9.1\times10^{-31}\,\text{kg}) enters a 0.05 T0.05\,\text{T} magnetic field with speed 3.0×107 m s−13.0\times10^{7}\,\text{m s}^{-1} at an angle of 30∘30^{\circ} to the field. The pitch of its helical path is approximately (a) 0.036 m0.036\,\text{m} (b) 0.018 m0.018\,\text{m} (c) 0.013 m0.013\,\text{m} (d) 0.026 m0.026\,\text{m}

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