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MATHEMATICS · Single correct · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Let hh be defined by h(x)=x2−9x−3h(x)=\dfrac{x^{2}-9}{x-3} for x≠3x\neq 3. The value h(3)h(3) is not defined. Determine the type of discontinuity of hh at x=3x=3. (a) Jump discontinuity, because the one-sided limits are finite but unequal. (b) No discontinuity, because the expression simplifies to x+3x+3 for all xx. (c) Removable discontinuity, because the limit exists and is finite. (d) Infinite discontinuity, because h(x)h(x) diverges to ∞\infty near x=3x=3.

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