A particle of mass is moving along a trajectory given by x = x_0 + a _1 t

PHYSICS · Single correct · CBSE · Physics · System of Particles and Rotational Motion · System of Particles and Rotational Motion

Problem

A particle of mass mm is moving along a trajectory given by x=x0+acos⁡ω1t,y=y0+bcos⁡ω2t.x = x_0 + a \cos \omega_1 t,\qquad y = y_0 + b \cos \omega_2 t. The torque, acting on the particle about the origin, at t=0t = 0 is: (1) m(−x0b+y0a)ω12k^m(-x_0 b + y_0 a)\omega_1^2 \hat{k} (2) +my0aω12k^+my_0 a \omega_1^2 \hat{k} (3) zero (4) −m(x0bω22−y0aω12)k^-m(x_0 b \omega_2^2 - y_0 a \omega_1^2) \hat{k}

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