Determine whether the series converges or diverges.

MATHEMATICS · Single correct · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

Determine whether the series ∑n=2∞1n(ln⁡n)3\displaystyle\sum_{n=2}^{\infty}\frac{1}{n(\ln n)^{3}} converges or diverges. (a) It diverges because substituting u=ln⁡xu=\ln x incorrectly gives ∫ ⁣1u du\int \! \frac{1}{u}\,du, which is unbounded. (b) It diverges because the logarithm grows too slowly, so the terms behave like the harmonic series 1/n1/n. (c) The series converges because ∫2∞1x(ln⁡x)3 dx\displaystyle\int_{2}^{\infty}\frac{1}{x(\ln x)^{3}}\,dx is finite; by the Integral Test, the series therefore converges. (d) It diverges; the Ratio Test gives a limit of 11, which demonstrates divergence.

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