For let and . A student tries to decide whether converges by checking the…

MATHEMATICS · Single correct · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

For n≥1n\ge 1 let an=2n2+1n3+5a_n=\dfrac{2n^{2}+1}{n^{3}+5} and bn=1nb_n=\dfrac{1}{n}. A student tries to decide whether ∑n=1∞an\displaystyle\sum_{n=1}^{\infty} a_n converges by checking the inequalities an≤bna_n\le b_n and an≥bna_n\ge b_n for large nn, but finds that neither inequality holds eventually. Which of the following best explains why a different comparison can still classify the series ∑n=1∞an\displaystyle\sum_{n=1}^{\infty} a_n? (a) The sign of ana_n alternates while bnb_n is always positive, so inequalities fail but an alternating–series argument succeeds. (b) Because ∑an\displaystyle\sum a_n can be viewed as the pp-series ∑1n2\sum \dfrac{1}{n^{2}} with p=2>1p=2>1, it converges regardless of any comparison with bnb_n.},{ (c) The ratio anbn\dfrac{a_n}{b_n} approaches a non-zero finite limit, so the two series share the same long-term behavior even without a fixed inequality. (d) Because bnb_n does not tend to 00, direct inequality tests are invalid, but another test works even though ∑bn\sum b_n diverges.

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