A proton has velocity components parallel to a uniform magnetic field of magnitude…

PHYSICS · Single correct · CBSE · Physics · Moving Charges and Magnetism · Moving Charges and Magnetism

Problem

A proton has velocity components

v_\parallel = 3.0\times10^{6}\,\text{m s}^{-1}

parallel to a uniform magnetic field of magnitude

0.050\,\text{T}

and

v_\perp = 4.0\times10^{6}\,\text{m s}^{-1}

perpendicular to the field. Given

m_p = 1.67\times10^{-27}\,\text{kg}

and

e = 1.6\times10^{-19}\,\text{C}

, the pitch of the helical path followed by the proton is approximately (a)

5.2\,\text{m}

(b)

4.0\,\text{m}

(c)

0.63\,\text{m}

(d)

2.0\,\text{m}