A water tank is an inverted right circular cone with a height of 12 m and a top…

MATHEMATICS · Multi-part · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

A water tank is an inverted right circular cone with a height of 12 m and a top radius of 4 m. Water is being pumped into the tank at a constant rate of 0.60 m3^3 min−1^{-1} while simultaneously draining through a valve at 0.15 m3^3 min−1^{-1}. The depth of the water at time tt minutes is h(t)h(t), measured vertically from the tip of the cone (its lowest point). Assume the water surface is always a circular cross-section whose radius varies with hh. (a) Express the radius of the water surface, rr, as a function of the current depth hh. Explain your reasoning. (b) Obtain a formula for the instantaneous rate of change of the water depth, dhdt\dfrac{dh}{dt}, in terms of hh. Clearly show how you relate volume change to depth change. (c) Calculate dhdt\dfrac{dh}{dt} when the water depth is 5.0 m. Include units and interpret the result. (d) Find the rate at which the radius of the water surface is changing at the same instant (h=5.0h=5.0 m). Indicate whether the surface is expanding or contracting and justify your answer.

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