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MATHEMATICS · Single correct · AP · Calculus AB · Differentiation: Composite, Implicit, and Inverse Functions · Differentiation: Composite, Implicit, and Inverse Functions
Problem 5. For g ( x ) = tan ( 3 x 2 ) ( 1 + 2 x ) 3 g(x)=\dfrac{\tan(3x^{2})}{(1+2x)^{3}} g ( x ) = ( 1 + 2 x ) 3 tan ( 3 x 2 ) g ′ ( 1 ) g'(1) g ′ ( 1 ) 6 sec 2 3 − 2 tan 3 9 \displaystyle \frac{6\sec^{2}3-2\tan3}{9} 9 6 sec 2 3 − 2 tan 3 6 sec 2 3 27 \displaystyle \frac{6\sec^{2}3}{27} 27 6 sec 2 3 6 sec 2 3 − 2 tan 3 27 \displaystyle \frac{6\sec^{2}3-2\tan3}{27} 27 6 sec 2 3 − 2 tan 3 sec 2 3 − 2 tan 3 27 \displaystyle \frac{\sec^{2}3-2\tan3}{27} 27 sec 2 3 − 2 tan 3 Browse the problem library