Consider , . If and for all and , then smallest positive integral value of…

MATHEMATICS · Single correct · AP · Calculus AB · Analytical Applications of Differentiation · Analytical Applications of Differentiation

Problem

Consider f(x)=cos⁡2x+2xλ2+(2λ+1)(λ−1)x2f(x)=\cos 2x+2x\lambda^2+(2\lambda+1)(\lambda-1)x^2, λ∈R\lambda\in R. If α≠β\alpha\ne\beta and f(α+β2)<f(α)+f(β)2f\left(\frac{\alpha+\beta}{2}\right)<\frac{f(\alpha)+f(\beta)}{2} for all α\alpha and β\beta, then smallest positive integral value of λ\lambda is (a) 1 (b) 2 (c) 3 (d) 4

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