CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Determinants · Determinants

Problem

∣bcbc′+b′cb′c′caca′+c′ac′a′abab′+a′ba′b′∣\begin{vmatrix} bc & bc' + b'c & b'c' \\ ca & ca' + c'a & c'a' \\ ab & ab' + a'b & a'b' \end{vmatrix} is equal to (a) (ab−a′b′)(bc−b′c′)(ca−c′a′)(ab - a'b')(bc - b'c')(ca - c'a') (b) (ab+a′b′)(bc+b′c′)(ca+c′a′)(ab + a'b')(bc + b'c')(ca + c'a') (c) (ab′−a′b)(bc′−b′c)(ca′−c′a)(ab' - a'b)(bc' - b'c)(ca' - c'a) (d) (ab′+a′b)(bc′+b′c)(ca′+c′a)(ab' + a'b)(bc' + b'c)(ca' + c'a)

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