Consider the function

MATHEMATICS · Multi-part · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Consider the function f(x)=x2+1f(x)=x^{2}+1. Show that lim⁡x→3f(x)=10\displaystyle \lim_{x\to 3} f(x)=10 by establishing an explicit relationship between ε\varepsilon and δ\delta. (a) Factor and simplify ∣f(x)−10∣|f(x)-10| to obtain an expression that involves ∣x−3∣|x-3| and ∣x+3∣|x+3|. (b) Restrict attention to values of xx satisfying ∣x−3∣<1|x-3|<1. Under this restriction, determine an upper bound for ∣x+3∣|x+3| and use it to produce an inequality of the form ∣f(x)−10∣⩽K∣x−3∣|f(x)-10| \leqslant K|x-3|, where KK is a positive constant you must specify. (c) For a given ε>0\varepsilon>0, choose a positive δ\delta that depends on ε\varepsilon and the constant KK so that ∣f(x)−10∣<ε|f(x)-10|<\varepsilon whenever ∣x−3∣<δ|x-3|<\delta and ∣x−3∣<1|x-3|<1. State the explicit formula for δ\delta. (d) Justify why the additional condition ∣x−3∣<1|x-3|<1 does not limit the generality of the proof, and conclude that the desired limit equals 1010. Provide a concise logical explanation rather than further algebra.

Related theory

Browse the problem library